\(\frac P{180} \times2πR\)
\(\frac{P}{180}\times π R^2\)
\(\frac P{360} \times 2π R\)
\(\frac P{ 270} \times 2π R^2\)
We know that area of sector of angle θ = \(\frac{θ}{360°} \times \pi r^2\)
Area of sector of angle P =\(\frac P { 360°}\times (\pi R^2)\) =\( (\frac{P}{720°)} (2 \pi R^2)\)
Hence, (D) is the correct answer.