To solve this problem, we need to analyze the thermal decomposition of silver nitrate (\( \text{AgNO}_3 \)) and determine the number of electrons in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons.
1. Analyzing the Decomposition Reaction:
The thermal decomposition of silver nitrate (\( \text{AgNO}_3 \)) produces two gases: silver (Ag) and nitrogen dioxide (\( \text{NO}_2 \)). The decomposition reaction can be written as:
\[ \text{2AgNO}_3 \xrightarrow{\Delta} 2\text{Ag} + 2\text{NO}_2 + \text{O}_2 \]
2. Identifying the Paramagnetic Gases:
The gases produced in the reaction are silver vapor (\( \text{Ag} \)) and nitrogen dioxide (\( \text{NO}_2 \)). Both are paramagnetic due to the presence of unpaired electrons. However, \( \text{NO}_2 \) has more unpaired electrons compared to silver, making it the gas with the higher number of unpaired electrons.
3. Determining the Number of Electrons in the Antibonding Molecular Orbitals:
In \( \text{NO}_2 \), the nitrogen dioxide molecule has an odd number of electrons in its molecular orbitals. The molecular orbital theory tells us that the electrons in antibonding orbitals are those that occupy the higher energy levels and correspond to the unpaired electrons. The number of unpaired electrons in \( \text{NO}_2 \) is 3, and the total number of electrons present in the antibonding molecular orbitals is 6 (2 electrons per antibonding orbital). Therefore, the total number of electrons in the antibonding molecular orbitals is 6.
Final Answer:
The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is 6.
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
Which of the following linear combinations of atomic orbitals will lead to the formation of molecular orbitals in homonuclear diatomic molecules (internuclear axis in z-direction)?
(1) \( 2p_z \) and \( 2p_x \)
(2) \( 2s \) and \( 2p_x \)
(3) \( 3d_{xy} \) and \( 3d_{x^2-y^2} \)
(4) \( 2s \) and \( 2p_z \)
(5) \( 2p_z \) and \( 3d_{x^2-y^2} \)
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
The Molecular Orbital Theory is a more sophisticated model of chemical bonding where new molecular orbitals are generated using a mathematical process called Linear Combination of Atomic Orbitals (LCAO).
Molecular Orbital theory is a chemical bonding theory that states that individual atoms combine together to form molecular orbitals. Due to this arrangement in MOT Theory, electrons associated with different nuclei can be found in different atomic orbitals. In molecular orbital theory, the electrons present in a molecule are not assigned to individual chemical bonds between the atoms. Rather, they are treated as moving under the influence of the atomic nuclei in the entire molecule.
