Question:
The width of the diffraction band varies
The width of the diffraction band varies
Updated On: Jan 18, 2023
- inversely as the wavelength
- directly as the width of the slit
- directly as the distance between the slit and the screen
- inversely as the size of the source from which the slit is illuminated
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Width of the diffraction band is given by
$\beta=\frac{\lambda D}{d}$
where $D=$ distance between slit and the screen
$\lambda=$ wavelength of light used and
$d=$ width of slit.
Hence, width of the diffraction band varies directly as the distance between the slit and the screen.
$\beta=\frac{\lambda D}{d}$
where $D=$ distance between slit and the screen
$\lambda=$ wavelength of light used and
$d=$ width of slit.
Hence, width of the diffraction band varies directly as the distance between the slit and the screen.
Was this answer helpful?
0
0
Top Questions on single slit diffraction
- In a single slit diffraction experiment, the aperture of the slit is 3 mm and the separation between the slit and the screen is 1.5 m. A monochromatic light of wavelength 600 nm is normally incident on the slit. Calculate the distance of (I) first order minimum, and (II) second order maximum, from the centre of the screen.
- CBSE CLASS XII - 2025
- Physics
- single slit diffraction
- In Young's double slit experiment, if the distance between the slits is 2 mm and the distance of the screen from the slits is 100 cm, the fringe width is 0.36 mm. If the distance between the slits is decreased by 0.5 mm and the distance of the screen from the slits is increased by 50 cm, the fringe width becomes
- AP EAPCET - 2025
- Physics
- single slit diffraction
- A single slit diffraction pattern is obtained using a beam of red light. If red light is replaced by blue light, then:
- WBJEE - 2025
- Physics
- single slit diffraction
- In Young's double slit experiment light of wavelength 500 nm is used to form interference pattern. A uniform glass plate of refractive index 1.5 and thickness 0.1 mm is introduced in the path of one of the interfering beams. The number of fringes that will shift due to this is
- COMEDK UGET - 2024
- Physics
- single slit diffraction
- Incident light of wavelength $ \lambda = 800 \, \text{nm} $ produces a diffraction pattern on a screen 1.5 m away when it passes through a single slit of width 0.5 mm. The distance between the first dark fringes on either side of the central bright fringe is
- COMEDK UGET - 2024
- Physics
- single slit diffraction
View More Questions
Questions Asked in KCET exam
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
- KCET - 2025
- Newtons Laws of Motion
- If \( A \) is a square matrix of order \( 3 \times 3 \), \( \det A = 3 \), then the value of \( \det(3A^{-1}) \) is:
- KCET - 2025
- Matrices
- The number of orbitals associated with 'N' shell of an atom is
- KCET - 2025
- Atomic Physics
- The system of equations \( 4x + 6y = 5 \) and \( 8x + 12y = 10 \) has:
- KCET - 2025
- Linear Equations
- If A and B are two matrices such that AB is an identity matrix and the order of matrix B is \(3 \times 4\), then the order of matrix A is:
- KCET - 2025
- Matrices
View More Questions
Concepts Used:
Single Slit Diffraction
In the single-slit diffraction experiment, we can examine the bending phenomenon of light or diffraction that causes light from a coherent source to hinder itself and produce an extraordinary pattern on the screen called the diffraction pattern.
Read More: Difference Between Diffraction and Interference
Central Maximum
