Question:

The value of van't Hoff factor, i, for CH₃COOH solution in water will be

Show Hint

For weak electrolytes like acetic acid, the van't Hoff factor is always between 1 and 2, depending on the degree of dissociation.
Updated On: Sep 9, 2025
  • Between 1 and 2
  • Less than 1
  • 2
  • 1
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding van't Hoff factor.
The van't Hoff factor (i) represents the number of particles a solute dissociates into when dissolved in a solvent. For a non-electrolyte, i = 1, while for an electrolyte, i depends on the degree of dissociation.
Step 2: Behavior of acetic acid in water.
Acetic acid (CH₃COOH) is a weak electrolyte. It undergoes partial dissociation in water: \[ \text{CH₃COOH} \rightleftharpoons \text{CH₃COO}⁻ + \text{H}⁺ \] Thus, it does not fully dissociate into ions, and the van't Hoff factor (i) is greater than 1 but less than (2)
Step 3: Conclusion.
The van't Hoff factor for CH₃COOH solution in water is between 1 and 2 because it partially dissociates into ions.
Final Answer: \[ \boxed{\text{The van't Hoff factor is between 1 and (2)}} \]
Was this answer helpful?
0
0

Top Questions on General Chemistry

View More Questions