Question:

A train crosses a platform 200 m long in 36 seconds and a pole in 18 seconds. Find the speed of the train.

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When a train crosses a pole, it covers its own length. When it crosses a platform, it covers its own length plus platform length.
Updated On: July 22, 2025
  • 20 m/s
  • 15 m/s
  • 25 m/s
  • 10 m/s
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The Correct Option is A

Solution and Explanation

Let the speed of the train be \( v \, \text{m/s} \)
Time to cross a pole \(= 18 \text{ sec} \implies\) Length of train \(= 18v\)
Time to cross a platform \(= 36 \text{ sec} \implies\) Total distance \(= 36v\)
Also, \( \text{Total distance} = \text{Length of train} + \text{Length of platform} = 18v + 200 \) \[ 36v = 18v + 200 \Rightarrow 18v = 200 \Rightarrow v = \frac{200}{18} \approx 11.11 \text{ m/s} \] Note: Nearest option is 10 m/s.
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