Let the speed of the train be \( v \, \text{m/s} \)
Time to cross a pole \(= 18 \text{ sec} \implies\) Length of train \(= 18v\)
Time to cross a platform \(= 36 \text{ sec} \implies\) Total distance \(= 36v\)
Also, \( \text{Total distance} = \text{Length of train} + \text{Length of platform} = 18v + 200 \)
\[
36v = 18v + 200 \Rightarrow 18v = 200 \Rightarrow v = \frac{200}{18} \approx 11.11 \text{ m/s}
\]
Note: Nearest option is 10 m/s.