In the given arrangement, we observe a Wheatstone Bridge.
For the bridge to be balanced:
\[ \frac{V_{AB}}{V_{AD}} = \frac{V_{BC}}{V_{CD}}. \]
Substituting values from the circuit:
\[ \frac{12}{6 + x} = \frac{0.5}{0.5}. \]
Simplify:
\[ 12(0.5) = (6 + x)(0.5). \]
\[ 6 = 3 + 0.5x \implies x = 6 \, \Omega. \]
Final Answer: \( x = 6 \, \Omega \).
Establish the relation between resistances of arms of Wheatstone bridge in balanced condition.
What is interference of light? Mention the condition for (A) constructive and (B) destructive interference.
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $