The value of net resistance of the network as shown in the given figure is :
- \( \frac{5}{2} \, \Omega \)
- \( \frac{15}{4} \, \Omega \)
- \( 6 \, \Omega \)
- \( \frac{30}{11} \, \Omega \)
The Correct Option is C
Solution and Explanation
The equivalent resistance is calculated as follows:
\[ R_{\text{eq}} = \frac{15 \times 10}{15 + 10} = \frac{150}{25} = 6 \, \Omega \]
Diode 2 is in reverse bias, so no current will flow through the branch containing it. It can be treated as a broken wire.
Diode 1 is in forward bias and will behave as a conducting wire. The new circuit becomes a simpler parallel and series resistor network.
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