Question:
The value of $\displaystyle\lim_{n\to\infty}\left(\frac{1}{n+1} +\frac{1}{n+2}+... +\frac{1}{6n}\right)$ is
The value of $\displaystyle\lim_{n\to\infty}\left(\frac{1}{n+1} +\frac{1}{n+2}+... +\frac{1}{6n}\right)$ is
Updated On: Jun 18, 2022
- $\log\, 2$
- $\log\, 6$
- $1$
- $\log\, 3$
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The Correct Option is B
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Concepts Used:
Integrals of Some Particular Functions
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
Integrals of Some Particular Functions:
- ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
- ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
- ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
- ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
- ∫1/√(a2 – x2) dx = sin-1(x/a) + C
- ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C
These are tabulated below along with the meaning of each part.
