\(\frac{26}{25}\)
\(\frac{25}{26}\)
\(\frac{50}{51}\)
\(\frac{52}{51}\)
\(\cot\left(\sum_{n=1}^{50} \tan^{-1}\left(\frac{1}{1+n+n^2}\right)\right)\)
\(\cot\left(\sum_{n=1}^{50} \tan^{-1}\left(\frac{n+1-n}{1+(n+1)n}\right)\right)\)
\(\cot\left(\sum_{n=1}^{50} (\tan^{-1}(n+1) - \tan^{-1}(n))\right)\)
\(\cot(\tan^{-1}(51) - \tan^{-1}(1))\)
\(\cot(\tan^{-1}(\frac{51-1}{1+51}))\)
\(\cot(\cot^{-1}(\frac{52}{50}))\)
\(=\frac{26}{25}\)
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
For $ \alpha, \beta, \gamma \in \mathbb{R} $, if $$ \lim_{x \to 0} \frac{x^2 \sin \alpha x + (\gamma - 1)e^{x^2} - 3}{\sin 2x - \beta x} = 3, $$ then $ \beta + \gamma - \alpha $ is equal to:
The inverse trigonometric functions are also called arcus functions or anti trigonometric functions. These are the inverse functions of the trigonometric functions with suitably restricted domains. Specifically, they are the inverse functions of the sine, cosine, tangent, cotangent, secant, and cosecant functions, and are used to obtain an angle from any of the angle’s trigonometric ratios. Inverse trigonometric functions are widely used in engineering, navigation, physics, and geometry.
Considering the domain and range of the inverse functions, following formulas are important to be noted:
Also, the following formulas are defined for inverse trigonometric functions.
cosec−1(cosec y) = y if -π/2 ≤ y ≤ π/2, y ≠ 0