In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
To determine the current in the RL circuit at the given instant:
1. Circuit Equation:
The governing equation is:
\[
V = L\frac{di}{dt} + IR
\]
Given values:
- \( V = 12 \) V
- \( L = 3 \) H
- \( R = 12 \) Ω
- \( \frac{di}{dt} = -8 \) A/s (current decreasing)
2. Calculation:
\[
12 = 3(-8) + I(12)
\]
\[
12 = -24 + 12I
\]
\[
36 = 12I
\]
\[
I = 3 \text{ A}
\]
The current at this instant is 3 A.
Two batteries of emf's \(3V \& 6V\) and internal resistances 0.2 Ω \(\&\) 0.4 Ω are connected in parallel. This combination is connected to a 4 Ω resistor. Find:
(i) the equivalent emf of the combination
(ii) the equivalent internal resistance of the combination
(iii) the current drawn from the combination
For the circuit shown in the figure, the active power supplied by the source is ________ W (rounded off to one decimal place).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
O\(_2\) gas will be evolved as a product of electrolysis of:
(A) an aqueous solution of AgNO3 using silver electrodes.
(B) an aqueous solution of AgNO3 using platinum electrodes.
(C) a dilute solution of H2SO4 using platinum electrodes.
(D) a high concentration solution of H2SO4 using platinum electrodes.
Choose the correct answer from the options given below :
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: