Question:
The value of C in (0, 2) satisfying the mean value theorem for the function \(f(x)=x(x-1)^2, x∈[0,2]\) is equal to
The value of C in (0, 2) satisfying the mean value theorem for the function \(f(x)=x(x-1)^2, x∈[0,2]\) is equal to
Updated On: May 1, 2024
- \(\frac{3}{4}\)
- \(\frac{4}{3}\)
- \(\frac{1}{3}\)
- \(\frac{2}{3}\)
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The Correct Option is B
Solution and Explanation
The correct answer is Option (B) : \(\frac{4}{3}\)
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