The molecular orbitals formed from 2s and 2p atomic orbitals are as fo
The problem asks for the total number of molecular orbitals that are formed by the combination of the 2s and 2p atomic orbitals from the two atoms in a diatomic molecule.
The formation of molecular orbitals (MOs) is explained by the Linear Combination of Atomic Orbitals (LCAO) theory. The fundamental principle of this theory is the conservation of orbitals, which states that the total number of molecular orbitals formed is always equal to the total number of atomic orbitals (AOs) that are combined.
\[ \text{Number of Molecular Orbitals formed} = \text{Number of Atomic Orbitals combined} \]Step 1: Identify the atomic orbitals contributed by the first atom.
For one atom, we are considering the atomic orbitals in the second principal energy level (n=2). These are:
So, the first atom contributes a total of \(1 + 3 = 4\) atomic orbitals.
Step 2: Identify the atomic orbitals contributed by the second atom.
Since the molecule is diatomic, there is a second atom. This second atom also contributes its 2s and 2p atomic orbitals for bonding.
The second atom also contributes a total of \(1 + 3 = 4\) atomic orbitals.
Step 3: Calculate the total number of atomic orbitals being combined.
The total number of atomic orbitals from both atoms is the sum of the orbitals contributed by each atom.
\[ \text{Total AOs} = (\text{AOs from atom 1}) + (\text{AOs from atom 2}) \] \[ \text{Total AOs} = 4 + 4 = 8 \]So, a total of 8 atomic orbitals are combined.
Step 4: Apply the principle of conservation of orbitals to find the total number of molecular orbitals.
According to the LCAO theory, the number of molecular orbitals formed must be equal to the number of atomic orbitals that were combined.
\[ \text{Number of MOs} = \text{Total AOs} = 8 \]These 8 molecular orbitals are typically designated as \( \sigma_{2s}, \sigma^*_{2s}, \sigma_{2p}, \pi_{2p_x}, \pi_{2p_y}, \pi^*_{2p_x}, \pi^*_{2p_y}, \sigma^*_{2p} \).
The total number of molecular orbitals formed is 8.
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
Which of the following linear combinations of atomic orbitals will lead to the formation of molecular orbitals in homonuclear diatomic molecules (internuclear axis in z-direction)?
(1) \( 2p_z \) and \( 2p_x \)
(2) \( 2s \) and \( 2p_x \)
(3) \( 3d_{xy} \) and \( 3d_{x^2-y^2} \)
(4) \( 2s \) and \( 2p_z \)
(5) \( 2p_z \) and \( 3d_{x^2-y^2} \)

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.