The sum of solutions of the equation cos\(\frac{cos\,x}{1+sin\,x}\)=|tan 2x|,x\(\in\)(\(-\frac{\pi}{2},\frac{\pi}{2}\))-(\(-\frac{\pi}{4},\frac{\pi}{4}\)) is:
The sum of solutions of the equation cos\(\frac{cos\,x}{1+sin\,x}\)=|tan 2x|,x\(\in\)(\(-\frac{\pi}{2},\frac{\pi}{2}\))-(\(-\frac{\pi}{4},\frac{\pi}{4}\)) is:
\(-\frac{11\pi}{6}\)
\(\frac{\pi}{10}\)
\(-\frac{7\pi}{30}\)
\(-\frac{\pi}{15}\)
The Correct Option is A
Solution and Explanation
The correct answer is option (A) : \(-\frac{11\pi}{6}\)
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