
Equation of tangent to the parabola at
P(\(\frac{8}{5},\frac{6}{5}\))
75x⋅85=160(y+\(\frac{6}{5}\))−192
⇒ 120x = 160y
⇒ 3x = 4y
The equation of the circle touching the given parabola at P can be taken as
(x−\(\frac{8}{5}\))2+(y−\(\frac{6}{5}\))2+λ(3x−4y)=0
If this circle touches the y-axis then
\(\frac{64}{25}\)+(y−65)2+λ(−4y)=0
⇒y2−2y(2λ+65)+4=0
⇒ D = 0
⇒(\(\frac{2λ+6}{6}\))2=4
⇒λ=\(\frac{2}{5}\) or −\(\frac{8}{5}\)
Radius = 1 or 4
Sum of diameter = 10
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2