Step 1: Understand the given line equation.
The line is given in symmetric form:
\[
\frac{x-3}{3} = \frac{y-2}{1} = \frac{z-1}{0}
\]
Since the denominator for \( z \) is \( 0 \), this indicates that \( z \) is constant.
From:
\[
\frac{z-1}{0} = k
\quad \Rightarrow \quad
z-1 = 0k
\quad \Rightarrow \quad
z=1
\]
Thus, \( z \) is fixed at \( z=1 \) for all points on the line.
Step 2: Analyze the direction.
Since \( z \) is constant and does not vary, the line lies completely in the plane \( z=1 \).
The direction ratios are:
\[
(3, 1, 0)
\]
which means the line moves along \( x \) and \( y \) but has no movement in \( z \).
Thus, the line is parallel to the x-y plane and perpendicular to the z-axis.
Step 3: Conclude the answer.
Hence, the line is perpendicular to the z-axis.