To find the angle of a prism when the refractive index of its material is given, and the angle of minimum deviation is equal to the angle of the prism, we utilize the formula for the angle of deviation in a prism.
The formula relating the refractive index (\( n \)), the angle of the prism (\( A \)), and the angle of minimum deviation (\( \delta_m \)) is given by:
\(n = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)
Given:
Substitute \( \delta_m = A \) in the formula:
\(n = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
Given \( n = 3 \), the equation becomes:
\(3 = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
We need to find the angle \( A \) such that the above equation holds.
By solving this equation using trigonometric identities and known values, we find:
\(A = 60^\circ\)
This solution matches with the provided options, confirming that the angle of the prism is indeed 60°.
Therefore, the correct answer is 60°.


For the circuit shown above, the equivalent gate is:
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is: