To find the angle of a prism when the refractive index of its material is given, and the angle of minimum deviation is equal to the angle of the prism, we utilize the formula for the angle of deviation in a prism.
The formula relating the refractive index (\( n \)), the angle of the prism (\( A \)), and the angle of minimum deviation (\( \delta_m \)) is given by:
\(n = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)
Given:
Substitute \( \delta_m = A \) in the formula:
\(n = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
Given \( n = 3 \), the equation becomes:
\(3 = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
We need to find the angle \( A \) such that the above equation holds.
By solving this equation using trigonometric identities and known values, we find:
\(A = 60^\circ\)
This solution matches with the provided options, confirming that the angle of the prism is indeed 60°.
Therefore, the correct answer is 60°.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 