Step 1: Analyze the circuit structure. - The given circuit consists of two NOT gates applied to \( A \) and \( B \), followed by two AND gates whose outputs feed into gate \( G \). - The final truth table indicates that \( Y \) is high for \( (A, B) = (0,0) \) and \( (1,1) \), but low otherwise.
Step 2: Identify the logical expression. Observing the output pattern, we recognize it corresponds to the NOR operation: \[ Y = \overline{A + B}. \]
Step 3: Select the appropriate gate. - The only logic gate that produces \( Y = \overline{A + B} \) is the NOR Gate.
- Thus, the correct choice for gate \( G \) is a NOR gate. Thus, the answer is \( \boxed{\text{NOR Gate}} \).
An \( \alpha \) particle is scattered from an Au target at rest as shown in the figure. \( D_1 \) and \( D_2 \) are the detectors to detect the scattered \( \alpha \) particle at an angle \( \theta \) and along the beam direction, respectively, as shown. The signals from \( D_1 \) and \( D_2 \) are converted to logic signals and fed to logic gates. When a particle is detected, the signal is 1 and is 0 otherwise. Which one of the following circuits detects the particle scattered at the angle \( \theta \) only?
A logic gate circuit is shown in the figure below. The correct combination for the input \( (P, Q) \) for which the output \( T = 1 \) is:
For the circuit shown above, the equivalent gate is: