
Step 1: Analyze the circuit structure. - The given circuit consists of two NOT gates applied to \( A \) and \( B \), followed by two AND gates whose outputs feed into gate \( G \). - The final truth table indicates that \( Y \) is high for \( (A, B) = (0,0) \) and \( (1,1) \), but low otherwise.
Step 2: Identify the logical expression. Observing the output pattern, we recognize it corresponds to the NOR operation: \[ Y = \overline{A + B}. \]
Step 3: Select the appropriate gate. - The only logic gate that produces \( Y = \overline{A + B} \) is the NOR Gate.
- Thus, the correct choice for gate \( G \) is a NOR gate. Thus, the answer is \( \boxed{\text{NOR Gate}} \).


For the circuit shown above, the equivalent gate is:

To obtain the given truth table, the following logic gate should be placed at G:
Which of the following circuits has the same output as that of the given circuit?
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: