According to Ohm's Law, Voltage (V) = Current (I) × Resistance (R)

According to Ohm's Law, Voltage (V) = Current (I) × Resistance (R)
From the Given equation, V = 3V, R = 200 ohm, I =?
Here, across the diode potential barrier ΔV=0.7 volts
The formula will look like, I=(V−ΔV)/R
Therefore, I= (3−0.7) /200
=0.0115 A
=11.5 mA
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The Correct Answer is (C): 11.5 mA

The Correct Answer is (C): 11.5 mA
This problem can also be solved by using Kirchoff's Law,
Then the equation will look like, 3-V- I (200) = 0
Here, V = 0.7V
Therefore, 3 - 0.7 - 200I = 0
⇒200I = 2.3
⇒ I = 2.3/200 = 0.0115
So, I = 11.5 mA
According to Kirchhoff's Current Law, no charge is wasted and the total current flowing into a junction in an electric circuit equals the charge leaving the node.
According to Kirchhoff's Voltage Law, the voltage in a closed network is equal to the total of all voltage drops in the loop and is zero.
In order to simplify the circuits and calculate the quantum of current and voltage in circuits, Kirchhoff's laws or Kirchhoff's rules are used to analyze complicated electrical circuits.
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