Question

The product (A) formed in the following reaction sequence is:

 

• A.
• B.
• C.
• D.

Hint:

In nucleophilic addition reactions, electron-withdrawing groups increase the reactivity of carbonyl compounds, while electron-donating groups decrease their reactivity. This principle is crucial in determining the reactivity order of different compounds.

Answer 1

The Correct Option is B

To determine the product (A) formed in the given reaction sequence, let's analyze each step of the transformation: 

1. Initial Reaction: The starting compound is propyne (CH₃-C≡CH).
2. Step 1: The reaction with \(Hg^{2+}\), \(H_2SO_4\) involves oxymercuration. In the presence of these reagents, propyne undergoes hydration, which typically leads to the formation of a ketone. In this case, it converts to acetone (CH₃-C(=O)-CH₃).
3. Step 2: The subsequent reaction with HCN introduces a cyanohydrin formation. The compound adds across the carbonyl group of acetone forming 2-hydroxy-2-methylpropanenitrile.
4. Step 3: The final step with H₂/Ni involves hydrogenation. The nitrile group (-CN) is reduced to an amine group (-CH₂NH₂).

So, the final product (A) formed is 2-amino-2-methylpropanol, depicted as:

This corresponds to the correct answer option.

Answer 2