In this reaction, aniline (\( C_6H_5NH_2 \)) undergoes diazotization with sodium nitrite (\( \text{NaNO}_2 \)) and hydrochloric acid at \( 0^\circ \text{C} \). The resulting diazonium salt reacts with copper chloride (\( \text{CuCl}_2 \)) to form chlorobenzene (\( C_6H_5Cl \)).
Thus, the product \( A \) is chlorobenzene, \( C_6H_5Cl \).
The Correct Answer is: \( C_6H_5Cl \)
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32