Question

The output voltage in the following circuit is (Consider ideal diode case): 

• A. \( -5 \, \text{V} \)
• B. \( +5 \, \text{V} \)
• C. \( 10 \, \text{V} \)
• D. \( 0 \, \text{V} \)

Hint:

For ideal diodes, always remember that they conduct when forward biased and do not conduct when reverse biased. In this case, the conducting diode pulls the output voltage to 0V.

Answer 1

The Correct Option is D

In the given circuit, we are considering ideal diodes.
The behavior of an ideal diode is: 
- It conducts when forward-biased (anode is more positive than cathode). 
- It does not conduct when reverse-biased.

Let's analyze the circuit step by step:

1. Diode \( D_1 \) is forward biased because its anode is at \( +5 \, \text{V} \) and its cathode is at \( V_{\text{out}} \).
2. Diode \( D_2 \) is reverse biased because its anode is at ground potential (0V) and its cathode is at \( V_{\text{out}} \). In this configuration:
- \( D_1 \) will conduct, and the output voltage at \( V_{\text{out}} \) will be 0V, since the ideal diode has no voltage drop when it conducts.
- \( D_2 \) will not conduct as it is reverse biased.

Thus, the output voltage \( V_{\text{out}} \) is \( 0 \, \text{V} \).