Which of the following circuits represents a forward biased diode?
To determine which circuits represent a forward biased diode, we need to understand the behavior of a diode in a circuit. A diode is forward biased when the anode (positive side) is connected to a higher potential than the cathode (negative side). This allows current to flow through the diode.
Let's analyze the provided options:
Upon evaluating the potential differences in the circuits shown in the original problem, it is clear that options (B), (C), and (E) have the diodes in a forward biased state.
Therefore, the correct answer is: (B), (C), and (E) only.
The output voltage in the following circuit is (Consider ideal diode case): 
In the following circuit, the reading of the ammeter will be: (Take Zener breakdown voltage = 4 V)


Let \( a \in \mathbb{R} \) and \( A \) be a matrix of order \( 3 \times 3 \) such that \( \det(A) = -4 \) and \[ A + I = \begin{bmatrix} 1 & a & 1 \\ 2 & 1 & 0 \\ a & 1 & 2 \end{bmatrix} \] where \( I \) is the identity matrix of order \( 3 \times 3 \).
If \( \det\left( (a + 1) \cdot \text{adj}\left( (a - 1) A \right) \right) \) is \( 2^m 3^n \), \( m, n \in \{ 0, 1, 2, \dots, 20 \} \), then \( m + n \) is equal to: