Which of the following circuits represents a forward biased diode?
To determine which circuits represent a forward biased diode, we need to understand the behavior of a diode in a circuit. A diode is forward biased when the anode (positive side) is connected to a higher potential than the cathode (negative side). This allows current to flow through the diode.
Let's analyze the provided options:
Upon evaluating the potential differences in the circuits shown in the original problem, it is clear that options (B), (C), and (E) have the diodes in a forward biased state.
Therefore, the correct answer is: (B), (C), and (E) only.
The output voltage in the following circuit is (Consider ideal diode case): 
In the following circuit, the reading of the ammeter will be: (Take Zener breakdown voltage = 4 V)

If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below