Question:
The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is ______
$ FeCl_3 + KOH + H_2C_2O_4 \rightarrow A $
The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is ______
$ FeCl_3 + KOH + H_2C_2O_4 \rightarrow A $
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For \( [M(AA)_3] \) type complexes, where AA is a symmetrical bidentate ligand, the complex is chiral and exists as two optical isomers (d and l forms).
Updated On: Sep 16, 2025
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Correct Answer: 2
Solution and Explanation
\( FeCl_3 + KOH + H_2C_2O_4 \rightarrow K_3[Fe(C_2O_4)_3] \)
\([Fe(C_2O_4)_3]^{3-} \text{ is } [M(AA)_3] \text{ type complex.} \)
So total optical isomers = 2
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