Step 1: Recall jadeite formula.
Jadeite = NaAlSi$_2$O$_6$ → requires Na in M2 site and Al in M1 site.
Step 2: Given composition.
(Ca$_{0.667}$Na$_{0.333}$Fe$^{2+}_{0.12}$Fe$^{3+}_{0.125}$Mg$_{0.546}$Al$_{0.208}$)Si$_2$O$_6$.
Step 3: Identify Na and Al contributions.
- Na = 0.333 mol.
- Al = 0.208 mol.
Jadeite component is controlled by Na occupancy since jadeite requires 1 Na and 1 Al per formula unit.
Step 4: Calculate mole fraction.
Na = 0.333 → fraction = 0.333.
Final Answer: \[ \boxed{0.333} \]