Step 1: Recall jadeite formula.
Jadeite = NaAlSi$_2$O$_6$ → requires Na in M2 site and Al in M1 site.
Step 2: Given composition.
(Ca$_{0.667}$Na$_{0.333}$Fe$^{2+}_{0.12}$Fe$^{3+}_{0.125}$Mg$_{0.546}$Al$_{0.208}$)Si$_2$O$_6$.
Step 3: Identify Na and Al contributions.
- Na = 0.333 mol.
- Al = 0.208 mol.
Jadeite component is controlled by Na occupancy since jadeite requires 1 Na and 1 Al per formula unit.
Step 4: Calculate mole fraction.
Na = 0.333 → fraction = 0.333.
Final Answer: \[ \boxed{0.333} \]


Consider the above reaction, what mass of CaCl₂ will be formed if 250 ml of 0.76 M HCl reacts with 1000 g of CaCO₃?
The figures I, II, and III are parts of a sequence. Which one of the following options comes next in the sequence at IV?

A color model is shown in the figure with color codes: Yellow (Y), Magenta (M), Cyan (Cy), Red (R), Blue (Bl), Green (G), and Black (K). Which one of the following options displays the color codes that are consistent with the color model?
