The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is:
\[ \text{Molarity} = \frac{\text{Mass of solute}}{\text{Volume of solution in L}} \]
Step 2: Apply the given values and compute the molarity. Final Conclusion: The molarity is \( 1.25 \times 10^{-1} \).The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____
If \[ f(x) = \int \frac{1}{x^{1/4} (1 + x^{1/4})} \, dx, \quad f(0) = -6 \], then f(1) is equal to: