Given: The strength of an oxidizing agent depends on its ability to accept electrons. A higher positive charge and smaller size typically make an ion a stronger oxidizing agent because the ion is more eager to accept electrons to achieve a stable electronic configuration.
- This is the 3+ cation of lanthanum (atomic number 71). - Although it is a highly charged ion, it is relatively large compared to other lanthanides. - **Conclusion**: It is a strong oxidizing agent but not as strong as other ions with higher charges and smaller sizes.
- This is the 2+ cation of europium (atomic number 63). - The Eu\(^{2+}\) ion is in the +2 oxidation state and is a stronger reducing agent compared to its +3 oxidation state. - **Conclusion**: Eu\(^{2+}\) is a reducing agent and not an oxidizing agent.
- This is the 4+ cation of terbium (atomic number 65). - The Tb\(^{4+}\) ion is highly charged and has a very high tendency to accept electrons, making it a very strong oxidizing agent. - **Conclusion**: The Tb\(^{4+}\) ion is the strongest oxidizing agent among the ions listed.
- This is the 3+ cation of cerium (atomic number 58). - The Ce\(^{3+}\) ion is a strong oxidizing agent but not as strong as Tb\(^{4+}\). - **Conclusion**: While a strong oxidizing agent, it is weaker compared to Tb\(^{4+}\).
The strongest oxidizing agent among the given ions is \( \boxed{\text{Tb}^{4+}} \), which is the most eager to accept electrons due to its high charge and smaller size compared to the other ions.