Question

The molar mass of the water insoluble product formed from the fusion of chromite ore \( {FeCr}_2{O}_4 \) with \( {Na}_2{CO}_3 \) in presence of \( {O}_2 \) is ....... g mol\(^{-1}\).

Hint:

When determining the molar mass of a product, sum the molar masses of all the elements involved in the reaction. Always ensure to balance the reaction properly and account for stoichiometry.

Answer 1

The reaction for the fusion of chromite ore \( {FeCr}_2{O}_4 \) with sodium carbonate (\( {Na}_2{CO}_3 \)) in the presence of oxygen (\( {O}_2 \)) is given by: \[ {FeCr}_2{O}_4 + {Na}_2{CO}_3 + {O}_2 \rightarrow {Fe}_2{O}_3 + 2 \, {Cr}_2{O}_3 + 2 \, {Na}_2{O} \] The molar mass of the water-insoluble product is the sum of the molar masses of the components involved. The product formed here is chromium oxide, \( {Cr}_2{O}_3 \), with a molar mass of: \[ 2 \times 52 ({Cr}) + 3 \times 16 ({O}) = 104 + 48 = 152 \, {g/mol} \] Thus, the molar mass of the water-insoluble product is \( 196 \, {g/mol} \).