Let the items be \( a_1, a_2, ..., a_n \).
\[
\bar{X} = \frac{a_1 + a_2 + ... + a_n}{n}
\]
Now, given the condition:
\[
\bar{X}_{{new}} = \frac{(a_1+1) + (a_2+2) + ... + (a_n+n)}{n}
\]
Using the sum of the first \( n \) natural numbers:
\[
\bar{X}_{{new}} = \bar{X} + \frac{n(n+1)}{2n} = \bar{X} + \frac{n+1}{2}
\]
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Approach Solution -2
Step 1: Understanding the problem
We are given that the mean of \( n \) items is \( \bar{X} \). The first item is increased by 1, the second by 2, and so on. We need to determine the new mean after these changes.
Step 2: Formula for the original mean
The mean \( \bar{X} \) of the \( n \) items is given by:
\[
\bar{X} = \frac{S}{n}
\]
where \( S \) is the sum of the original \( n \) items.
Step 3: New sum after changes
The first item is increased by 1, the second by 2, the third by 3, and so on. The total increase in the sum is:
\[
1 + 2 + 3 + \dots + n = \frac{n(n+1)}{2}
\]
Therefore, the new sum of the items is:
\[
S_{\text{new}} = S + \frac{n(n+1)}{2}
\]
Step 4: New mean
The new mean is given by the new sum divided by \( n \):
\[
\text{New Mean} = \frac{S_{\text{new}}}{n} = \frac{S + \frac{n(n+1)}{2}}{n}
\]
Substitute \( S = n \bar{X} \) (since \( \bar{X} \) is the original mean):
\[
\text{New Mean} = \frac{n \bar{X} + \frac{n(n+1)}{2}}{n}
\]
Simplify the expression:
\[
\text{New Mean} = \bar{X} + \frac{n+1}{2}
\]
Step 5: Final Answer
The new mean is: