Let the items be \( a_1, a_2, ..., a_n \).
\[
\bar{X} = \frac{a_1 + a_2 + ... + a_n}{n}
\]
Now, given the condition:
\[
\bar{X}_{{new}} = \frac{(a_1+1) + (a_2+2) + ... + (a_n+n)}{n}
\]
Using the sum of the first \( n \) natural numbers:
\[
\bar{X}_{{new}} = \bar{X} + \frac{n(n+1)}{2n} = \bar{X} + \frac{n+1}{2}
\]