The standard deviation measures the spread of data, which is unaffected by a constant shift. If each number is increased by 5, the mean changes, but the standard deviation remains the same. Given the original standard deviation is 2:
\[
\text{New standard deviation} = 2
\]
To confirm, recall that standard deviation is calculated as:
\[
\sigma = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}
\]
If each \( x_i \) is increased by 5, the new values are \( x_i + 5 \), and the new mean is \( \bar{x} + 5 = 15 + 5 = 20 \). The deviations become:
\[
(x_i + 5) - (\bar{x} + 5) = x_i - \bar{x}
\]
Thus, the standard deviation remains unchanged. The new standard deviation is:
\[
\boxed{2}
\]