Question

The maximum vertical height to which a man can throw a ball is $136 \,m$ The maximum horizontal distance upto which he can throw the same ball is:

• A. $68\, m$
• B. $136\, m$
• C. $192\, m$
• D. $272\, m$

Answer 1

The Correct Option is D

The maximum vertical height is related to the maximum velocity as: \[ H_{\text{max}} = \frac{v^2}{2g} \] Given \(H_{\text{max}} = 136 \, \text{m}\), solve for \(v^2\): \[ v^2 = 2g H_{\text{max}} = 2 \cdot 9.8 \cdot 136 = 2 \cdot 136 \, \text{(using \(g \approx 9.8 \, \text{m/s}^2\))}. \] The maximum horizontal range \(R_{\text{max}}\) is given by: \[ R_{\text{max}} = \frac{v^2}{g} = 2H_{\text{max}} = 2 \cdot 136 = 272 \, \text{m}. \]