
To determine the major product of the given reaction, we need to analyze the structure and reactivity of the compound involved. The question provides us with the compound 6-Phenylhepta-2,4-diene.
Step 1: Analyze the structure: The compound is a conjugated diene with phenyl substitution at position 6. It has the structure:
Step 2: Electrophilic addition reaction: In electrophilic additions, conjugated dienes like hepta-2,4-diene can undergo 1,2-addition (kinetic control) or 1,4-addition (thermodynamic control).
Step 3: Identify stability: Due to conjugation, electrons can delocalize, making certain products more stable. The reaction typically forms a product where the double bonds remain conjugated, as seen with 6-Phenylhepta-2,4-diene. Conjugated double bonds stabilize the molecule through resonance.
| Option | Product Description |
|---|---|
| 2-Phenylhepta-2,4-diene | Phenyl group at position 2, different from input structure |
| 6-Phenylhepta-3,5-diene | Position of double bonds is shifted, may not be favored |
| 6-Phenylhepta-2,4-diene | Original compound, conjugated diene structure, favored by resonance |
| 2-Phenylhepta-2,5-diene | Non-conjugated, phenyl at position 2 |
Conclusion: The most stable, resonance-stabilized structure is 6-Phenylhepta-2,4-diene, which is the major product.
Chlorobenzene to biphenyl
Match the LIST-I with LIST-II

Choose the correct answer from the options given below:
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ A \in \mathbb{R} $ be a matrix of order 3x3 such that $$ \det(A) = -4 \quad \text{and} \quad A + I = \left[ \begin{array}{ccc} 1 & 1 & 1 \\2 & 0 & 1 \\4 & 1 & 2 \end{array} \right] $$ where $ I $ is the identity matrix of order 3. If $ \det( (A + I) \cdot \text{adj}(A + I)) $ is $ 2^m $, then $ m $ is equal to: