Question:

Match the LIST-I with LIST-II 

Choose the correct answer from the options given below:

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- Carbocation: \(\text{sp}^2\), 6 electrons, planar - Free radical: 7 electrons, can be \(\text{sp}^2\) or \(\text{sp}^3\) - Nucleophile: "nucleus loving" (e\(^-\) donor) - Electrophile: "electron loving" (e\(^-\) acceptor)
Updated On: Apr 14, 2025
  • A-III, B-III, C-I, D-IV
  • A-III, B-IV, C-II, D-I
  • A-IV, B-II, C-III, D-I
  • A-III, B-IV, C-I, D-II
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The Correct Option is D

Solution and Explanation

Correct Matching:
- A: Carbocation - III (sp2 hybridized carbon with empty p-orbital)
- B: C-Free radical - IV (sp2/sp3 hybridized carbon with one unpaired electron)
- C: Nucleophile - I (Species that can supply a pair of electrons)
- D: Electrophile - II (Species that can receive a pair of electrons)

Explanation:
- Carbocations are electron-deficient species with sp2 hybridization and empty p-orbital
- Free radicals have one unpaired electron and can be sp2 or sp3 hybridized
- Nucleophiles are electron-rich species that donate electron pairs
- Electrophiles are electron-deficient species that accept electron pairs

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