Match the LIST-I with LIST-II
Choose the correct answer from the options given below:
Correct Matching:
- A: Carbocation - III (sp2 hybridized carbon with empty p-orbital)
- B: C-Free radical - IV (sp2/sp3 hybridized carbon with one unpaired electron)
- C: Nucleophile - I (Species that can supply a pair of electrons)
- D: Electrophile - II (Species that can receive a pair of electrons)
Explanation:
- Carbocations are electron-deficient species with sp2 hybridization and empty p-orbital
- Free radicals have one unpaired electron and can be sp2 or sp3 hybridized
- Nucleophiles are electron-rich species that donate electron pairs
- Electrophiles are electron-deficient species that accept electron pairs
Chlorobenzene to biphenyl
The net current flowing in the given circuit is ___ A.
If the equation \( a(b - c)x^2 + b(c - a)x + c(a - b) = 0 \) has equal roots, where \( a + c = 15 \) and \( b = \frac{36}{5} \), then \( a^2 + c^2 \) is equal to .