Conversion of Chlorobenzene to Biphenyl:
The conversion of chlorobenzene (C₆H₅Cl) to biphenyl (C₆H₅-C₆H₅) involves a reaction known as the **Wurtz-Fittig Reaction**. This reaction is a type of cross-coupling reaction where two aryl halides are coupled in the presence of sodium metal.
Reaction:
2 C₆H₅Cl + Na → C₆H₅-C₆H₅ + 2 NaCl
Mechanism:
1. The reaction is carried out in dry ether and requires heat. Sodium metal donates electrons to the chlorobenzene, generating a phenyl radical (C₆H₅•) and sodium chloride (NaCl).
2. The phenyl radicals couple together to form biphenyl (C₆H₅-C₆H₅).
Conditions:
- Sodium metal (Na) is used as a reducing agent.
- The reaction takes place in the presence of anhydrous ether to prevent moisture from interfering with the reaction.
Conclusion:
By heating chlorobenzene with sodium metal in ether, chlorobenzene undergoes a Wurtz-Fittig reaction to form biphenyl.
Identify A in the following reaction. 
For the reaction, \(N_{2}O_{4} \rightleftharpoons 2NO_{2}\) graph is plotted as shown below. Identify correct statements.
A. Standard free energy change for the reaction is 5.40 kJ \(mol^{-1}\).
B. As \(\Delta G\) in graph is positive, \(N_{2}O_{4}\) will not dissociate into \(NO_{2}\) at all.
C. Reverse reaction will go to completion.
D. When 1 mole of \(N_{2}O_{4}\) changes into equilibrium mixture, value of \(\Delta G = -0.84 \text{ kJ mol}^{-1}\).
E. When 2 mole of \(NO_{2}\) changes into equilibrium mixture, \(\Delta G\) for equilibrium mixture is \(-6.24 \text{ kJ mol}^{-1}\).
Choose the correct answer from the following.
