Ensure consistent units for turns per meter and current when applying the formula.
Step 1: Use the formula for magnetic intensity - Magnetic intensity is given by: \[ H = n I, \] where \(n\) is the number of turns per meter and \(I\) is the current. Given: \[ H = 1.6 \times 10^3 \, \text{A/m}, \, n = 8 \, \text{turns/cm} = 800 \, \text{turns/m}. \]
Step 2: Solve for the current - \[ I = \frac{H}{n} = \frac{1.6 \times 10^3}{800}. \] Simplifying: \[ I = 2 \, \text{A}. \]
Final Answer: The current flowing through the solenoid is 2 A.
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: