The radius \( r \) of the circular path of a charged particle moving in a magnetic field is given by the formula: \[ r = \frac{mv}{qB} \] where:
- \( m \) is the mass of the particle,
- \( v \) is the speed of the particle,
- \( q \) is the charge of the particle,
- \( B \) is the magnetic field strength.
For a proton, \( m_p \) and charge \( q_p = e \), and for a deuteron, \( m_d = 2m_p \) and charge \( q_d = e \).
Since both particles are moving with the same speed and in the same magnetic field, the ratio of the radii is: \[ \frac{r_p}{r_d} = \frac{\frac{m_p v}{eB}}{\frac{2m_p v}{eB}} = \frac{1}{2} \] Hence, the correct answer is (B) 1 : 2.