Question

The horizontal component of Earth’s magnetic field at a place is 3 × 10^-5 T. If the dip at that place is 45°, the resultant magnetic field at that place is

• A. \(\frac{3}{\sqrt2}\times10^{-5}\ T\)
• B. \(\frac{3}{2}\sqrt3\times10^{-5}\ T\)
• C. \(3\sqrt2\times10^{-5}\ T\)
• D. \(3\times10^{-5}\ T\)

Answer 1

The Correct Option is C

The correct answer is (C) : \(3\sqrt2\times10^{-5}\ T\).