Question:

The magnetic behavior of Li2O, Na2O2 and KO2, respectively, are

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For magnetic properties of oxides:
   O\(^{2-}\) and O\(_2^{2-}\) ions are diamagnetic due to paired electrons.
   O\(_2^-\) ions are paramagnetic due to the presence of unpaired electrons.

Updated On: Jan 9, 2025
  • Paramagnetic, paramagnetic and diamagnetic
  • Diamagnetic, diamagnetic and paramagnetic
  • Paramagnetic, diamagnetic and paramagnetic
  • Diamagnetic, paramagnetic and diamagnetic
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The Correct Option is B

Solution and Explanation

1. Li\(_2\)O (Lithium Oxide): Contains O\(^{2-}\) ions, which have a completely filled electronic configuration.
Magnetic Behaviour: Diamagnetic.
2.Na\(_2\)O\(_2\) (Sodium Peroxide): Contains O\(_2^{2-}\) ions, which also have a completely paired electronic configuration.
Magnetic Behaviour: Diamagnetic.
3. KO\(_2\) (Potassium Superoxide): Contains O\(_2^-\) ions, which have one unpaired electron.
Magnetic Behaviour: Paramagnetic.
Final Answer: \((4)\) Diamagnetic, Diamagnetic, Paramagnetic.

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