For magnetic properties of oxides:
O\(^{2-}\) and O\(_2^{2-}\) ions are diamagnetic due to paired electrons.
O\(_2^-\) ions are paramagnetic due to the presence of unpaired electrons.
1. Li\(_2\)O (Lithium Oxide): Contains O\(^{2-}\) ions, which have a completely filled electronic configuration.
Magnetic Behaviour: Diamagnetic.
2.Na\(_2\)O\(_2\) (Sodium Peroxide): Contains O\(_2^{2-}\) ions, which also have a completely paired electronic configuration.
Magnetic Behaviour: Diamagnetic.
3. KO\(_2\) (Potassium Superoxide): Contains O\(_2^-\) ions, which have one unpaired electron.
Magnetic Behaviour: Paramagnetic.
Final Answer: \((4)\) Diamagnetic, Diamagnetic, Paramagnetic.
The following data were obtained for the reaction: \[ 2NO(g) + O_2(g) \rightarrow 2N_2O(g) \] at different concentrations:
The rate law of this reaction is:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: