For magnetic properties of oxides:
O\(^{2-}\) and O\(_2^{2-}\) ions are diamagnetic due to paired electrons.
O\(_2^-\) ions are paramagnetic due to the presence of unpaired electrons.
1. Li\(_2\)O (Lithium Oxide): Contains O\(^{2-}\) ions, which have a completely filled electronic configuration.
Magnetic Behaviour: Diamagnetic.
2.Na\(_2\)O\(_2\) (Sodium Peroxide): Contains O\(_2^{2-}\) ions, which also have a completely paired electronic configuration.
Magnetic Behaviour: Diamagnetic.
3. KO\(_2\) (Potassium Superoxide): Contains O\(_2^-\) ions, which have one unpaired electron.
Magnetic Behaviour: Paramagnetic.
Final Answer: \((4)\) Diamagnetic, Diamagnetic, Paramagnetic.
The cycloalkene (X) on bromination consumes one mole of bromine per mole of (X) and gives the product (Y) in which C : Br ratio is \(3:1\). The percentage of bromine in the product (Y) is _________ % (Nearest integer).
Given:
\[ \text{H} = 1,\quad \text{C} = 12,\quad \text{O} = 16,\quad \text{Br} = 80 \]
Consider an A.P. $a_1,a_2,\ldots,a_n$; $a_1>0$. If $a_2-a_1=-\dfrac{3}{4}$, $a_n=\dfrac{1}{4}a_1$, and \[ \sum_{i=1}^{n} a_i=\frac{525}{2}, \] then $\sum_{i=1}^{17} a_i$ is equal to
