Faraday's law states that an emf is induced in a coil when the magnetic flux through the coil changes with time.
Magnetic flux (\( \Phi \)) is given by:
\( \Phi = \vec{B} \cdot \vec{A} = BA \cos \theta \)
where \( \vec{B} \) is the magnetic field, \( \vec{A} \) is the area vector of the coil, and \( \theta \) is the angle between the magnetic field and the area vector.
An induced emf can be produced by rotating the coil (C) and by changing the area of the coil (D) (Option 2).
Induced emf can be induced in a coil by changing magnetic flux. And 𝜙 = 𝐵⃗ . 𝑑𝐴⃗⃗⃗⃗⃗ By rotating coil, angle between coil and magnetic field changes and hence flux changes. By changing area, magnetic flux changes.
A circular coil of diameter 15 mm having 300 turns is placed in a magnetic field of 30 mT such that the plane of the coil is perpendicular to the direction of the magnetic field. The magnetic field is reduced uniformly to zero in 20 ms and again increased uniformly to 30 mT in 40 ms. If the EMFs induced in the two time intervals are \( e_1 \) and \( e_2 \) respectively, then the value of \( e_1 / e_2 \) is:
Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of $\frac{1}{\sqrt{2}}$ Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of $10 \mathrm{~cm} / \mathrm{s}$, induced emf between points A and E is _______ mV.} 

Let \( a \in \mathbb{R} \) and \( A \) be a matrix of order \( 3 \times 3 \) such that \( \det(A) = -4 \) and \[ A + I = \begin{bmatrix} 1 & a & 1 \\ 2 & 1 & 0 \\ a & 1 & 2 \end{bmatrix} \] where \( I \) is the identity matrix of order \( 3 \times 3 \).
If \( \det\left( (a + 1) \cdot \text{adj}\left( (a - 1) A \right) \right) \) is \( 2^m 3^n \), \( m, n \in \{ 0, 1, 2, \dots, 20 \} \), then \( m + n \) is equal to: