Th correct option is(A): 12 kms–1
\(v_{esc}=\sqrt\frac{2GM}{R}=\sqrt\frac{2G}{R}×p×\frac{4}{3}{\pi}R^3\)
\(⇒v_{esc}∝R\sqrt{p}\)
\(⇒\frac{(v_esc)B}{(vesc)A}=1\)
⇒ (vesc)B = 12 km/s
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is:
The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.

Read More: Difference Between Speed and Velocity