Th correct option is(A): 12 kms–1
\(v_{esc}=\sqrt\frac{2GM}{R}=\sqrt\frac{2G}{R}×p×\frac{4}{3}{\pi}R^3\)
\(⇒v_{esc}∝R\sqrt{p}\)
\(⇒\frac{(v_esc)B}{(vesc)A}=1\)
⇒ (vesc)B = 12 km/s

The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.

Read More: Difference Between Speed and Velocity