The element that does not belong to the same period of the remaining elements (modern periodic table) is:
Show Hint
- Palladium
- Iridium
- Osmium
- Platinum
The Correct Option is A
Solution and Explanation
In the modern periodic table, elements are arranged in periods (rows) based on their atomic numbers. To determine which element does not belong to the same period as the others, we need to identify the periods of the given elements:
- Palladium (Pd): atomic number 46, located in period 5.
- Iridium (Ir): atomic number 77, located in period 6.
- Osmium (Os): atomic number 76, located in period 6.
- Platinum (Pt): atomic number 78, located in period 6.
The elements Iridium, Osmium, and Platinum are all in period 6. Palladium, however, is in period 5, making it the element that does not belong to the same period as the others. Therefore, Palladium is the correct answer.
Top Questions on Periodic Table
- Which among the following electronic configurations belong to main group elements?
A. [Ne]3s$^1$
B. [Ar]3d$^3$4s$^2$
C. [Kr]4d$^5$3s$^2$5p$^5$
D. [Ar]3d$^10$4s$^1$
E. [Rn]5f$^7$6d$^2$7s$^2$
Choose the correct answer from the options given below:- NEET (UG) - 2025
- Chemistry
- Periodic Table
- Which of the following electronegativity order is incorrect?
- JEE Main - 2025
- Chemistry
- Periodic Table
Match List-I with List-II
Choose the correct answer from the options given below:- CUET (PG) - 2025
- Nano Science
- Periodic Table
- On descending the group from Li to Na to K to Rb to Cs
(A) Metallic radius increases
(B) Melting point and boiling point decrease
(C) Density decreases
(D) Ionization energy decreases
Choose the correct answer from the options given below:- CUET (PG) - 2025
- Nano Science
- Periodic Table
- Arrange the following in the order of increasing first ionization energy
(A) Beryllium (Be)
(B) Boron (B)
(C) Lithium (Li)
(D) Carbon (C)
Choose the correct answer from the options given below:- CUET (PG) - 2025
- Nano Science
- Periodic Table
Questions Asked in JEE Main exam
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:
- JEE Main - 2025
- Parabola
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
- JEE Main - 2025
- Conic sections
Let $ A \in \mathbb{R} $ be a matrix of order 3x3 such that $$ \det(A) = -4 \quad \text{and} \quad A + I = \left[ \begin{array}{ccc} 1 & 1 & 1 \\2 & 0 & 1 \\4 & 1 & 2 \end{array} \right] $$ where $ I $ is the identity matrix of order 3. If $ \det( (A + I) \cdot \text{adj}(A + I)) $ is $ 2^m $, then $ m $ is equal to:
- JEE Main - 2025
- Determinants
- An air bubble of radius 0.1 cm lies at a depth of 20 cm below the free surface of a liquid of density 1000 kg/m\(^3\). If the pressure inside the bubble is 2100 N/m\(^2\) greater than the atmospheric pressure, then the surface tension of the liquid in SI units is (use \(g = 10 \, {m/s}^2\)).
- JEE Main - 2025
- Surface Tension
- A force of 49 N acts tangentially at the highest point of a sphere (solid of mass 20 kg) kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is:
- JEE Main - 2025
- Quantum Mechanics