Question:
The element that does not belong to the same period of the remaining elements (modern periodic table) is:
The element that does not belong to the same period of the remaining elements (modern periodic table) is:
Show Hint
When analyzing elements in the periodic table, always check their atomic number to determine their period. Elements in the same period have the same number of electron shells.
Updated On: May 10, 2025
- Palladium
- Iridium
- Osmium
- Platinum
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
In the modern periodic table, elements are arranged in periods (rows) based on their atomic numbers. To determine which element does not belong to the same period as the others, we need to identify the periods of the given elements:
- Palladium (Pd): atomic number 46, located in period 5.
- Iridium (Ir): atomic number 77, located in period 6.
- Osmium (Os): atomic number 76, located in period 6.
- Platinum (Pt): atomic number 78, located in period 6.
The elements Iridium, Osmium, and Platinum are all in period 6. Palladium, however, is in period 5, making it the element that does not belong to the same period as the others. Therefore, Palladium is the correct answer.
Was this answer helpful?
3
0
Top Questions on Periodic Table
- Correct order of first ionisation energy of B, In, Ga, and Al is:
- UPCATET - 2025
- Chemistry
- Periodic Table
- Incorrect match of IUPAC symbol of elements with its respective atomic number is:
- UPCATET - 2025
- Chemistry
- Periodic Table
- The energy of second Bohr orbit of hydrogen atom is \(-3.4 \, \text{eV}\). The energy of the fourth Bohr orbit of the He\(^+\) ion will be
- AP EAPCET - 2025
- Chemistry
- Periodic Table
- a, b, c, d are electromagnetic radiations. Frequencies of a, b, c are $3 \times 10^{15$ Hz, respectively, whereas the wavelength of c, d are 400 nm, 750 nm, respectively. The increasing order of their energies is}
- AP EAPCET - 2025
- Chemistry
- Periodic Table
- The radius of fourth orbit in \( He^+ \) ion is \( R_1 \) pm and radius of third orbit in \( Li^{2+} \) ion is \( R_2 \) pm. The value of \( (R_1 - R_2) \) in pm is:
- AP EAPCET - 2025
- Chemistry
- Periodic Table
View More Questions
Questions Asked in JEE Main exam
- Let \( f(x) = \frac{x - 5}{x^2 - 3x + 2} \). If the range of \( f(x) \) is \( (-\infty, \alpha) \cup (\beta, \infty) \), then \( \alpha^2 + \beta^2 \) equals to.
- JEE Main - 2025
- Functions
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
- A force of 49 N acts tangentially at the highest point of a sphere (solid of mass 20 kg) kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is:
- JEE Main - 2025
- Quantum Mechanics
- The number of 6-letter words, with or without meaning, that can be formed using the letters of the word "MATHS" such that any letter that appears in the word must appear at least twice is:
- JEE Main - 2025
- Calculus
- Let integers \( a, b \in [-3, 3] \) be such that \( a + b \neq 0 \). \(\text{Then the number of all possible ordered pairs}\) \( (a, b) \), \(\text{for which}\) \[ \left| \frac{z - a}{z + b} \right| = 1 \quad \text{and} \quad \left| \begin{matrix} z + 1 & \omega & \omega^2 \\ \omega^2 & 1 & z + \omega \\ \omega^2 & 1 & z + \omega \end{matrix} \right| = 1, \] \(\text{is equal to:}\)
- JEE Main - 2025
- Complex numbers
View More Questions