The element that does not belong to the same period of the remaining elements (modern periodic table) is:
Show Hint
- Palladium
- Iridium
- Osmium
- Platinum
The Correct Option is A
Solution and Explanation
In the modern periodic table, elements are arranged in periods (rows) based on their atomic numbers. To determine which element does not belong to the same period as the others, we need to identify the periods of the given elements:
- Palladium (Pd): atomic number 46, located in period 5.
- Iridium (Ir): atomic number 77, located in period 6.
- Osmium (Os): atomic number 76, located in period 6.
- Platinum (Pt): atomic number 78, located in period 6.
The elements Iridium, Osmium, and Platinum are all in period 6. Palladium, however, is in period 5, making it the element that does not belong to the same period as the others. Therefore, Palladium is the correct answer.
Top Questions on Periodic Table
- Which among the following electronic configurations belong to main group elements?
A. [Ne]3s$^1$
B. [Ar]3d$^3$4s$^2$
C. [Kr]4d$^5$3s$^2$5p$^5$
D. [Ar]3d$^10$4s$^1$
E. [Rn]5f$^7$6d$^2$7s$^2$
Choose the correct answer from the options given below:- NEET (UG) - 2025
- Chemistry
- Periodic Table
Why is \( Cr^{2+} \) strongly reducing while \( Mn^{3+} \) is strongly oxidizing?
- CBSE CLASS XII - 2025
- Chemistry
- Periodic Table
- Given below are two statements: Statement (I): According to the Law of Octaves, the elements were arranged in the increasing order of their atomic number.
Statement (II): Meyer observed a periodically repeated pattern upon plotting physical properties of certain elements against their respective atomic numbers. In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- Periodic Table
- Which of the following options represents the correct ionic radii in Å of N3-, O2-, and F- respectively?
- TS EAMCET - 2025
- Chemistry
- Periodic Table
Which of the following Statements are NOT true about the periodic table?
A. The properties of elements are a function of atomic weights.
B. The properties of elements are a function of atomic numbers.
C. Elements having similar outer electronic configuration are arranged in the same period.
D. An element's location reflects the quantum numbers of the last filled orbital.
E. The number of elements in a period is the same as the number of atomic orbitals available in the energy level that is being filled.- JEE Main - 2025
- Chemistry
- Periodic Table
Questions Asked in JEE Main exam
Resonance in X$_2$Y can be represented as
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is:- JEE Main - 2025
- Chemical bonding and molecular structure
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
- JEE Main - 2025
- permutations and combinations
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
- JEE Main - 2025
- Calculus
- An electric dipole of mass \( m \), charge \( q \), and length \( l \) is placed in a uniform electric field \( E = E_0 \hat{i} \). When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be:
- JEE Main - 2025
- Electric Dipole
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]
- JEE Main - 2025
- Law Of Chemical Equilibrium And Equilibrium Constant