\(λ_p ∝ λ^{2}_e\)
\(λ_p ∝ λ_e\)
\(λ_p ∝ \sqrtλ_e\)
\(λ_p ∝ \sqrt{\frac{1}{λ_e}}\)
The correct answer is (A) : \(λ_p ∝ λ^{2}_e\)
\(λ_p = \frac{h}{p} = \frac{hc}{E} .... (i)\)
\(λ_e = \frac{h}{\sqrt{2mE}} .... (ii)\)
From (i) and (ii)
\(λ_p ∝ λ^{2}_e\)
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