Question:

The current gain of a common emitter amplifier is $69$ . If the emitter current is $7.0 \,mA$, collector current is :

Updated On: Apr 28, 2025
  • 9.6 mA
  • 6.9 mA
  • 0.69 mA
  • 69 mA
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The Correct Option is B

Solution and Explanation

$\beta=69=\frac{I_{C}}{I_{B}}$ $\alpha=\frac{\beta}{1+\beta}=\frac{69}{70}=\frac{I_{C}}{I_{E}}$ $I_{C}=I_{E}\times\frac{69}{70}$ $=\frac{69}{70}\times7$ $=6.9$ mA
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Concepts Used:

P-n Junction

A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.

Biasing conditions for the p-n Junction Diode:

in p-n junction diode two operating regions are there:

  • P-type
  • N-type

There are three biasing conditions for p-n junction diode are as follows:

  • Zero bias: When there is no external voltage applied to the p-n junction diode.
  • Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
  • Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.