
In electrophilic substitution reactions, the reactivity of aromatic compounds is influenced by the substituents attached to the benzene ring. These substituents can be either activating or deactivating, and they can direct the incoming electrophile to specific positions on the ring.
Let's examine the given compounds:
Analysis:
Therefore, the reactivity order in electrophilic substitution is:
B > A > C > D
This means Toluene is the most reactive, followed by Benzene, then Chlorobenzene, and Nitrobenzene being the least reactive.
The reactivity of aromatic compounds in electrophilic substitution reactions depends on the presence and nature of substituents attached to the benzene ring. Substituents can be classified as either activating or deactivating groups based on their electronic influence on the ring.
Let's analyze the given compounds:
Considering these effects, the order of reactivity in electrophilic substitution reactions is determined by the ability of the substituents to donate or withdraw electrons.
The correct order of reactivity is:
\( B > A > C > D \)
Explanation:
Thus, option \( B > A > C > D \) is the correct order.
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)
Given below are two statements:
Statement (I): Alcohols are formed when alkyl chlorides are treated with aqueous potassium hydroxide by elimination reaction.
Statement (II): In alcoholic potassium hydroxide, alkyl chlorides form alkenes by abstracting the hydrogen from the $ \beta $-carbon.
In the light of the above statements, choose the most appropriate answer from the options given below:
In the following substitution reaction: 
0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion, produced 0.9 g H₂O. Molar mass of (X) is ___________g mol\(^{-1}\).
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to: