The correct option with order of melting points of the pairs (Mn, Fe), (Tc, Ru) and (Re, Os) is:
Show Hint
- \( {Fe}<{Mn}, \ {Ru}<{Tc} \ {and} \ {Re}<{Os} \)
- \( {Mn}<{Fe}, \ {Tc}<{Ru} \ {and} \ {Os}<{Re} \)
- \( {Mn}<{Fe}, \ {Tc}<{Ru} \ {and} \ {Re}<{Os} \)
- \( {Fe}<{Mn}, \ {Ru}<{Tc} \ {and} \ {Os}<{Re} \)
The Correct Option is C
Solution and Explanation
- The melting point of Mn is lower than Fe because Mn has a lower atomic number and a less stable crystal structure compared to Fe.
- The melting point of Tc is lower than Ru due to the differences in atomic structure and bonding.
- The melting point of Re is lower than Os because Os has a higher atomic number and stronger metallic bonding, leading to a higher melting point. Thus, the correct answer is \( {Mn}<{Fe}, \ {Tc}<{Ru} \ {and} \ {Re}<{Os} \).
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