Question

The correct increasing order of stability of the complexes based on \( \Delta \) value is:

• A. IV < III < II < I
• B. III < II < IV < I
• C. I < II < IV < III
• D. II < III < I < IV

Hint:

To determine the stability order based on \( \Delta \), consider the ligand field splitting energy and the ligand's electron-donating or withdrawing effects.

Answer 1

The Correct Option is C

To determine the stability order of complexes based on the \( \Delta \) value, we need to consider the crystal field splitting energy \((\Delta)\). Generally, the greater the \( \Delta \), the more stable the complex.
Given options for the stability order according to their \( \Delta \):

1. Option 1: IV < III < II < I
2. Option 2: III < II < IV < I
3. Option 3: I < II < IV < III
4. Option 4: II < III < I < IV

The correct order based on increasing stability, as indicated, is I < II < IV < III. This order suggests that complex I has the lowest \( \Delta \), making it least stable, while complex III has the highest \( \Delta \), making it most stable.

Conclusion: The correct increasing order of stability based on \( \Delta \) value is I < II < IV < III.