Question

The compounds that produce CO$_2$ with aqueous NaHCO$_3$ solution are:

• A. A and C Only
• B. A, B, and E Only
• C. A, C, and D Only
• D. A and B Only

Hint:

Carboxylic acids and other sufficiently acidic functional groups react with bicarbonates to release carbon dioxide, a useful reaction for identifying certain organic functional groups.

Answer 1

The Correct Option is C

Aqueous sodium bicarbonate ($ NaHCO_3 $) solution is a weak base. Carboxylic acids react with $ NaHCO_3 $ to produce carbon dioxide ($ CO_2 $). Phenols are generally weaker acids than carboxylic acids and do not react with $ NaHCO_3 $ unless they are substituted with strong electron-withdrawing groups.

A. Benzoic acid ($ C_6H_5COOH $): Carboxylic acids react with $ NaHCO_3 $ to produce $ CO_2 $.
This compound produces $ CO_2 $.

B. Phenol ($ C_6H_5OH $): Phenols are generally weaker acids than carbonic acid and do not react with $ NaHCO_3 $.
This compound does NOT produce $ CO_2 $.

C. Picric acid (2,4,6-trinitrophenol): This is a strongly acidic phenol due to the presence of three nitro groups. It can react with $ NaHCO_3 $ to produce $ CO_2 $.
This compound produces $ CO_2 $.

D. Cyclohexanecarboxylic acid ($ C_6H_{11}COOH $): Carboxylic acids react with $ NaHCO_3 $ to produce $ CO_2 $.
This compound produces $ CO_2 $.

E. 4-Methoxyphenol: It is a very weak phenol and does not react with $ NaHCO_3 $, even slightly.
This compound does NOT produce $ CO_2 $.

Therefore, the compounds that produce $ CO_2 $ when reacted with aqueous $ NaHCO_3 $ are A, C, and D.

Final Answer:
The final answer is $ (3)\ A,\ C\ \text{and}\ D\ \text{only} $.