Using Boolean logic, an AND gate can be constructed by combining NAND gates as follows: \[ {AND}(A,B) = {NAND}({NAND}(A,B), {NAND}(A,B)) \] This means the output of a NAND gate is fed into another NAND gate acting as an inverter, which results in AND operation.
The second circuit (Option B) shows this correct configuration.
Match the LIST-I with LIST-II
| LIST-I (Logic Gates) | LIST-II (Expressions) | ||
|---|---|---|---|
| A. | EX-OR | I. | \( A\bar{B} + \bar{A}B \) |
| B. | NAND | II. | \( A + B \) |
| C. | OR | III. | \( AB \) |
| D. | EX-NOR | IV. | \( \bar{A}\bar{B} + AB \) |
Choose the correct answer from the options given below:
