Question:
An 8-bit microcontroller with memory map from 8000H to 9FFFH stores how many bytes?
An 8-bit microcontroller with memory map from 8000H to 9FFFH stores how many bytes?
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Use \( \text{End} - \text{Start} + 1 \) for address range calculations.
Updated On: June 02, 2025
- 8193
- 8191
- 8192
- 8000
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The Correct Option is C
Solution and Explanation
\[
\text{Range} = 9FFFH - 8000H + 1 = (40959 - 32768 + 1) = 8192\ \text{bytes}
\]
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