Let the speed of the stream be v km/hr. Then, - Speed upstream = (5 − v) km/hr - Speed downstream = (5 + v) km/hr
Time taken upstream for 12 km = 12 / (5 − v) Time taken downstream for 12 km = 12 / (5 + v)
Given that upstream takes 1 hour more:
12 / (5 − v) = 12 / (5 + v) + 1
Simplify: 12 / (5 − v) − 12 / (5 + v) = 1
12[(5 + v) − (5 − v)] / [(5 − v)(5 + v)] = 1
12(2v) / (25 − v²) = 1
24v = 25 − v²
v² + 24v − 25 = 0
Solve quadratic: v = 1 (valid, since speed must be positive).
Effective speeds: - Upstream = 5 − 1 = 4 km/hr - Downstream = 5 + 1 = 6 km/hr
Time for N km upstream = N / 4 Time for N km downstream = N / 6 Total = N/4 + N/6 = (5N) / 12
Total ≥ 2 hours:
(5N)/12 ≥ 2
5N ≥ 24
N ≥ 24/5 = 4.8
Thus, the minimum possible value of N is 4.8 km.