To solve the problem, we need to determine the time it takes for two trains traveling towards each other to meet, accounting for their different start times and speeds.
- Relative Speed: When two objects move towards each other, their relative speed is the sum of their individual speeds.
- Time Difference: If one train starts earlier, the distance it covers during that time must be considered.
- Meeting Point: The point where the combined distances covered by both trains equals the total distance between them.
Distance between stations = \( 300 \text{ km} \)
Speed of Train A = \( 60 \text{ km/h} \)
Speed of Train B = \( 90 \text{ km/h} \)
Train A starts \( 1 \text{ hour} \) earlier than Train B
Let \( t \) be the time (in hours) Train B travels before meeting Train A.
Then, Train A travels for \( t + 1 \) hours.
Distance covered by Train A = \( 60 \times (t + 1) \)
Distance covered by Train B = \( 90 \times t \)
Since the total distance is 300 km:
\[
60(t + 1) + 90t = 300
\]
\[
60t + 60 + 90t = 300
\]
\[
150t + 60 = 300
\]
\[
150t = 240 \Rightarrow t = \frac{240}{150} = 1.6 \text{ hours}
\]
The two trains will meet 1.6 hours (or 1 hour 36 minutes) after Train B starts.